(5x^2-4x-5)(4x+7)=0

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Solution for (5x^2-4x-5)(4x+7)=0 equation: 


Simplifying
(5x2 + -4x + -5)(4x + 7) = 0

Reorder the terms:
(-5 + -4x + 5x2)(4x + 7) = 0

Reorder the terms:
(-5 + -4x + 5x2)(7 + 4x) = 0

Multiply (-5 + -4x + 5x2) * (7 + 4x)
(-5(7 + 4x) + -4x * (7 + 4x) + 5x2 * (7 + 4x)) = 0
((7 * -5 + 4x * -5) + -4x * (7 + 4x) + 5x2 * (7 + 4x)) = 0
((-35 + -20x) + -4x * (7 + 4x) + 5x2 * (7 + 4x)) = 0
(-35 + -20x + (7 * -4x + 4x * -4x) + 5x2 * (7 + 4x)) = 0
(-35 + -20x + (-28x + -16x2) + 5x2 * (7 + 4x)) = 0
(-35 + -20x + -28x + -16x2 + (7 * 5x2 + 4x * 5x2)) = 0
(-35 + -20x + -28x + -16x2 + (35x2 + 20x3)) = 0

Combine like terms: -20x + -28x = -48x
(-35 + -48x + -16x2 + 35x2 + 20x3) = 0

Combine like terms: -16x2 + 35x2 = 19x2
(-35 + -48x + 19x2 + 20x3) = 0

Solving
-35 + -48x + 19x2 + 20x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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